The e.m.f. of a Daniell cell at 298 K is E1. [figure] When the concentration of ZnSO4 is 1.0 M and that of CuSO4 is 0.01 M, the e.m.f. changed to E2. What is the relationship between E1 and E2?
- E1 > E2
- E1 < E2
- E1 = E2
- E2 = 0 E1
Answer
(1) E1 > E2
Solution
Cell reaction: Zn + Cu2+ Zn2+ + Cu, n = 2
Nernst equation: Ecell = E cell - 0.0592 [Zn2+][Cu2+]
E1 = E cell - 0.0592 0.011.0
= E cell + 0.059 V
E2 = E cell - 0.0592 1.00.01
= E cell - 0.059 V
E1 > E2
Answer: (1)