A transverse wave on a string is described by y=3 (36t+0.018x+ /4 ), where x, y are in cm and t in seconds. The least distance between the two successive crests in the wave is cm. (Nearest integer) ( =3.14)
Answer
349
Solution
Comparing with y=A ( t+kx+ ): k=0.018 cm-1
Distance between two successive crests = = 2 k
⇒ = 2 3.140.018 cm=348.9 cm
∴ 349 cm
Answer: 349