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Motion in a Straight Line · Question 17

NEET 2018MCQMedium📈 Topic in 25% papers+4−1
1

A toy car with charge q moves on a frictionless horizontal plane surface under the influence of a uniform electric field E. Due to the force q E, its velocity increases from 0 to 6 m s-1 in one second duration. At that instant the direction of the field is reversed. The car continues to move for two more seconds under the influence of this field. The average velocity and the average speed of the toy car between 0 to 3 seconds are respectively

  1. 2 m s-1, 4 m s-1
  2. 1 m s-1, 3 m s-1
  3. 1 m s-1, 3.5 m s-1
  4. 1.5 m s-1, 3 m s-1

Answer

(2) 1 m s-1, 3 m s-1

Solution

Acceleration: a = 6 - 01 = 6 m s-2

0 to 1 s: s1 = 12 6 12 = 3 m (forward)

Field reversed ⇒ a = -6 m s-2

1 s to 2 s: the car stops (6 - 6 1 = 0); s2 = 6 1 - 12 6 12 = 3 m (forward)

2 s to 3 s: starts from rest backward; s3 = 12 6 12 = 3 m (backward)

Displacement = 3 + 3 - 3 = 3 m; distance = 3 + 3 + 3 = 9 m

⇒ Average velocity = 33 = 1 m s-1

∴ Average speed = 93 = 3 m s-1

Answer: (2)

NEET 2018

Keep practising — Motion in a Straight Line

2

Preeti reached the metro station and found that the escalator was not working. She walked up the stationary escalator in time t1. On another day, if she remains stationary on the moving escalator, then the escalator takes her up in time t2. The time taken by her to walk up on the moving escalator will be

  1. t1t2t2-t1
  2. t1t2t2+t1
  3. t1-t2
  4. t1+t22
NEET 2017
3

If the velocity of a particle is v = At + Bt2, where A and B are constants, then the distance travelled by it between 1 s and 2 s is

  1. 32A + 73B
  2. A2 + B3
  3. 32A + 4B
  4. 3A + 7B
NEET 2016 (Phase 1)
4

Two cars P and Q start from a point at the same time in a straight line and their positions are represented by xP(t) = (at + bt2) and xQ(t) = (ft - t2). At what time do the cars have the same velocity ?

  1. a-f1+b
  2. a+f2(b-1)
  3. a+f2(1+b)
  4. f-a2(1+b)
NEET 2016 (Phase 2)
5

A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v(x) = x-2n, where and n are constants and x is the position of the particle. The acceleration of the particle as a function of x, is given by

  1. -2 2x-2n+1
  2. -2n 2e-4n+1
  3. -2n 2x-2n-1
  4. -2n 2x-4n-1
AIPMT 2015 (Cancelled)
6

A stone falls freely under gravity. It covers distances h1, h2 and h3 in the first 5 seconds, the next 5 seconds and the next 5 seconds respectively. The relation between h1, h2 and h3 is

  1. h2 = 3h1 and h3 = 3h2
  2. h1 = h2 = h3
  3. h1 = 2h2 = 3h3
  4. h1 = h23 = h35
NEET 2013
7

The displacement 'x' (in meter) of a particle of mass 'm' (in kg) moving in one dimension under the action of a force, is related to time 't' (in sec) by t = x + 3. The displacement of the particle when its velocity is zero, will be

  1. 4 m
  2. 0 m (zero)
  3. 6 m
  4. 2 m
NEET 2013 (Karnataka)
8

A stone is dropped from a height h. It hits the ground with a certain momentum P. If the same stone is dropped from a height 100% more than the previous height, the momentum when it hits the ground will change by

  1. 68%
  2. 41%
  3. 200%
  4. 100%
AIPMT 2012 (Mains)
9

The motion of a particle along a straight line is described by equation x = 8 + 12t - t3 where x is in metre and t in second. The retardation of the particle when its velocity becomes zero is

  1. 24 m s-2
  2. zero
  3. 6 m s-2
  4. 12 m s-2
AIPMT 2012 (Prelims)
10

A particle covers half of its total distance with speed v1 and the rest half distance with speed v2. Its average speed during the complete journey is

  1. v1+v22
  2. v1v2v1+v2
  3. 2v1v2v1+v2
  4. v12v22v12+v22
AIPMT 2011 (Mains)
11

A boy standing at the top of a tower of 20 m height drops a stone. Assuming g = 10 m s-2, the velocity with which it hits the ground is

  1. 10.0 m/s
  2. 20.0 m/s
  3. 40.0 m/s
  4. 5.0 m/s
AIPMT 2011 (Prelims)

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