When an object is shot from the bottom of a long smooth inclined plane kept at an angle 60 with horizontal, it can travel a distance x1 along the plane. But when the inclination is decreased to 30 and the same object is shot with the same velocity, it can travel x2 distance. Then x1 : x2 will be :
- 1 : 2
- 2 : 1
- 1 : 3
- 1 : 2 3
Answer
(3) 1 : 3
Solution
On a smooth incline, retardation along the plane = g
Using v2 = u2 - 2as with v = 0:
x = u22g
x1x2 = 30 60
= 1/2 3/2 = 1 3
x1 : x2 = 1 : 3
Answer: (3)