The amplitude of the charge oscillating in a circuit decreases exponentially as Q = Q0e-Rt/2L, where Q0 is the charge at t = 0 s. The time at which charge amplitude decreases to 0.50Q0 is nearly: [Given that R = 1.5 , L = 12 mH, (2) = 0.693]
- 19.01 ms
- 11.09 ms
- 19.01 s
- 11.09 s
Answer
(2) 11.09 ms
Solution
0.5Q0 = Q0e-Rt/2L
Rt2L = 2
t = 2L 2R
= 2 12 10-3 0.6931.5
= 11.09 10-3 s = 11.09 ms
Answer: (2)