An -particle moves in a circular path of radius 0.83 cm in the presence of a magnetic field of 0.25 Wb/m2. The de Broglie wavelength associated with the particle will be
- 1 A
- 0.1 A
- 10 A
- 0.01 A
Answer
(4) 0.01 A
Solution
For circular motion in a magnetic field:
r = mvqB p = mv = qBr
de Broglie wavelength:
= hp = hqBr
For an -particle, q = 2e = 3.2 10-19 C
= 6.6 10-343.2 10-19 0.25 0.83 10-2
1 10-12 m = 0.01 A
Answer: (4)