The threshold frequency for a photosensitive metal is 3.3 1014 Hz. If light of frequency 8.2 1014 Hz is incident on this metal, the cut-off voltage for the photoelectron emission is nearly
- 1 V
- 2 V
- 3 V
- 5 V
Answer
(2) 2 V
Solution
Einstein's photoelectric equation: eV0 = h( - 0)
V0 = h( - 0)e
= 6.6 10-34 (8.2 - 3.3) 10141.6 10-19
= 6.6 4.9 10-201.6 10-19
2.0 V
Answer: (2)