The electron in the hydrogen atom jumps from excited state (n = 3) to its ground state (n = 1) and the photons thus emitted irradiate a photosensitive material. If the work function of the material is 5.1 eV, the stopping potential is estimated to be (the energy of the electron in nth state En = - 13.6n2 eV)
- 5.1 V
- 12.1 V
- 17.2 V
- 7 V
Answer
(4) 7 V
Solution
Energy of the emitted photon: h = E3 - E1
= - 13.69 - (-13.6 ) = 13.6 89
= 12.09 eV
Einstein's equation: eV0 = h - 0 = 12.09 - 5.1 = 6.99 eV
V0 7 V
Answer: (4)