Let a1,a2, ,a2024 be an Arithmetic Progression such that a1+(a5+a10+a15+ +a2020)+a2024=2233. Then a1+a2+a3+ +a2024 is equal to .
Answer
11132
Solution
Pair a5 with a2020, a10 with a2015, …: indices add to 2025 ⇒ each pair =a1+a2024
404 terms ⇒ 202 pairs; with the pair a1+a2024 itself ⇒ 203 pairs
⇒ 203(a1+a2024)=2233 ⇒ a1+a2024=11
S2024=1012 11
∴ =11132
Answer: 11132