The stored charge in the capacitor in steady state of the following circuit is μC. [figure]
Answer
200
Solution
[figure]
Steady state: no current flows in the capacitor branch, so the 10 Ω in series with the capacitor carries none
voltage across the capacitor = voltage across the vertical 4 Ω
12 Ω is connected directly across the 12 V cell and does not affect the other path
Right loop: 4+4+2=10 Ω, in parallel with the vertical 10 Ω 5 Ω
Path from the cell: 5+5+2=12 Ω I= 1212=1 A
Equal 10 Ω branches 0.5 A flows through the vertical 4 Ω
VC=0.5 4=2 V
Q=CVC=100 2 V=200
Answer: 200