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Current Electricity · Question 2

JEE Main 2026 (Online) 6th April Morning ShiftNumericalMedium📈 Topic in 19% papers+4
1

Refer to the circuit diagram given below. The heat generated across the 6 resistance in 100 second is 100 J. The value of is . (Nearest integer) [figure]

Answer

3477

Solution

[figure]

Take VY=0. The 2 V cell (positive plate on the left) makes the left wire +2 V. The 3 V cell (positive plate towards the 6 Ω) keeps the end of the 6 Ω resistor at +3 V. Let VX=V.

Junction rule at X (current in through 3 Ω = currents out through 4 Ω and 6 Ω):

2-V3= V-04+ V-36

× 12 ⇒ 8-4V=3V+2V-6 ⇒ 9V=14 ⇒ V= 149 V

Current in 6 Ω: i= 3-V6= 13/96= 1354 A (towards X)

Heat in 100 s: H=i2Rt= ( 1354 )2 6 100

= 1692916 600=34.77 J = 3477100 J

∴ =3477

Answer: 3477

JEE Main 2026 (Online) 6th April Morning Shift

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2

Two cells of emfs 1 V and 2 V and internal resistance 2 and 1 , respectively connected in parallel, gave a current of 1 A through an external resistance. If the polarity of one cell is reversed, then value of current through the external resistance will be 5 A. The value of is .

JEE Main 2026 (Online) 6th April Evening Shift
3

Refer to the figure given below. The values of I1, I2 and I3 are . [figure]

  1. I1=2.5 A, I2=1.875 A, I3=1.875 A
  2. I1=1.875 A, I2=2.5 A, I3=1.875 A
  3. I1=1.875 A, I2=1.875 A, I3=2.5 A
  4. I1=2.5 A, I2=2.5 A, I3=1.875 A
JEE Main 2026 (Online) 5th April Morning Shift
4

Refer to the figure given below, current between terminals A and B is A. [figure]

  1. 12.5
  2. 1.25
  3. 7.5
  4. 5
JEE Main 2026 (Online) 5th April Morning Shift
5

Under steady state condition the potential difference across the capacitor in the circuit is V. [figure]

  1. 0.5
  2. 1.5
  3. 0
  4. 2
JEE Main 2026 (Online) 5th April Evening Shift
6

When an external resistance of 5 is connected across terminals of a cell, a current of 0.25 A flows through it. When the 5 resistor is replaced by a 2 resistor, a current of 0.5 A flows through it. The internal resistance of the cell is .

JEE Main 2026 (Online) 5th April Evening Shift
7

The voltage and the current between A and B points shown in the circuit are . [figure]

  1. 24 V, 12 A
  2. 24 V, 4 A
  3. 18 V, 12 A
  4. 27 V, 4 A
JEE Main 2026 (Online) 4th April Morning Shift
8

Two resistors of 200 Ω and 400 Ω are connected in series with a battery of 100 V. A bulb rated at 200 V, 100 W is connected across the 400 Ω resistance. The potential drop across the bulb is V.

  1. 25
  2. 50
  3. 66.6
  4. 100
JEE Main 2026 (Online) 2nd April Evening Shift
9

For the two cells having same EMF E and internal resistance r, the current passing through the external resistor 6 is same when both the cells are connected either in parallel or in series. The value of internal resistance r is .

  1. 3
  2. 6
  3. 4
  4. 9
JEE Main 2026 (Online) 28th January Morning Shift
10

In the potentiometer, when the cell in the secondary circuit is shunted with 4 resistance, the balance is obtained at the length 120 cm of wire. Now when the same cell is shunted with 12 resistance, the balance is shifted to a length of 180 cm. The internal resistance of cell is

  1. 4
  2. 12
  3. 6
  4. 3
JEE Main 2026 (Online) 28th January Morning Shift
11

The equivalent resistance between the points A and B in the following circuit is x5 . The value of x is . [figure]

JEE Main 2026 (Online) 28th January Morning Shift

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