When an external resistance of 5 is connected across terminals of a cell, a current of 0.25 A flows through it. When the 5 resistor is replaced by a 2 resistor, a current of 0.5 A flows through it. The internal resistance of the cell is .
Answer
1
Solution
E=I(R+r)
Case 1: E=0.25(5+r)
Case 2: E=0.5(2+r)
0.25(5+r)=0.5(2+r)
1.25+0.25r=1+0.5r 0.25r=0.25
r=1 (and E=1.5 V)
Answer: 1