In the potentiometer, when the cell in the secondary circuit is shunted with 4 resistance, the balance is obtained at the length 120 cm of wire. Now when the same cell is shunted with 12 resistance, the balance is shifted to a length of 180 cm. The internal resistance of cell is
- 4
- 12
- 6
- 3
Answer
(1) 4
Solution
With a shunt R, terminal voltage of the cell V = ERR + r, and V l (balancing length).
V1V2 = 44 + r 1212 + r = 120180
4(12 + r)12(4 + r) = 23
3(12 + r) = 2(12 + 3r)
36 + 3r = 24 + 6r
r = 4
Answer: (1)