A cell can be balanced against 110 cm and 100 cm of potentiometer wire, respectively without and with being short circuited through a resistance of 10 . Its internal resistance is
- 2.0 ohm
- zero
- 1.0 ohm
- 0.5 ohm
Answer
(3) 1.0 ohm
Solution
Balancing length without the shunt (emf) l1 = 110 cm; with the 10 shunt (terminal p.d.) l2 = 100 cm.
r = R ( l1l2 - 1 )
= 10 ( 110100 - 1 )
= 1.0
Answer: (3)