1
When phenol is treated with CHCl3 and NaOH, the product formed is
- benzaldehyde
- salicylaldehyde
- salicylic acid
- benzoic acid
Answer
(2) salicylaldehyde
Solution
This is the Reimer–Tiemann reaction.
As per NCERT, on treating phenol with chloroform in the presence of sodium hydroxide, a -CHO group is introduced at the ortho position of the benzene ring; the intermediate is hydrolysed in the presence of alkali to give salicylaldehyde (2-hydroxybenzaldehyde).
C6H5OH [(ii) H+](i) CHCl3, aq. NaOH o-HOC6H4CHO
Answer: (2)
AIPMT 2002