Let H : x2a2- y2b2=1 be a hyperbola such that the distance between its foci is 6 and the distance between its directrices is 83. If the line x= intersects the hyperbola H at the points A and B such that the area of the triangle AOB is 4 15, where O is the origin, then 2 equals
- 12
- 16
- 24
- 25
Answer
(2) 16
Solution
[figure]
2ae=6 ae=3 and 2ae= 83 ae= 43
a2=ae ae=4, a=2, e= 32
b2=a2 (e2-1 )=4 ( 94-1 )=5, so H: x24- y25=1
At x= : y2=5 ( 24-1 ) =2 5 ( 2-4 )4= 5 ( 2-4 )
Area of AOB = 12 | |= | |2 5 ( 2-4 )=4 15
2 5 ( 2-4 )=4 16 15
4-4 2-192=0 ( 2-16 ) ( 2+12 )=0
2=16
Answer: (2)