Let P(3 , 2 ), 0, be a point on the ellipse x29+ y24=1, Q be a point on the circle x2+y2-14x-14y+82=0 and R be a point on the line x+y=5 such that the centroid of the triangle PQR is (2+ , 3+ 23 ). Then the sum of the ordinates of all possible points R is :
- 6
- 2
- 4
- 8
Answer
(4) 8
Solution
Let Q(x1, y1) and R(x2, y2) with x2+y2=5.
Centroid: 3 +x1+x23=2+ x1+x2=6
2 +y1+y23=3+ 23 y1+y2=9
x1+y1=15-(x2+y2)=10, so Q lies on the line x+y=10.
Circle: (x-7)2+(y-7)2=16, centre C(7, 7), radius 4. Put Q(t, 10-t):
(t-7)2+(3-t)2=16 t2-10t+21=0 t=3, 7
1(3, 7) or Q2(7, 3)
R=(6-x1, 9-y1) 1(3, 2) or R2(-1, 6) (both lie on x+y=5)
[figure]
Sum of ordinates of R =2+6=8
Answer: (4)