The ground state energy of hydrogen atom is -13.6 eV. When its electron is in the first excited state, its excitation energy is
- 10.2 eV
- 0
- 3.4 eV
- 6.8 eV
Answer
(1) 10.2 eV
Solution
En = - 13.6n2 eV
First excited state: n = 2 E2 = - 13.64 = -3.4 eV
Excitation energy = E2 - E1
= -3.4 - (-13.6)
= 10.2 eV
Answer: (1)