A 4.0 cm long straight wire carrying a current of 8 A is placed perpendicular to a uniform magnetic field of strength 0.15 T. The magnetic force on the wire is mN.
Answer
48
Solution
F = BIl 90
= 0.15 8 0.04 = 0.048 N
F = 48 mN
Answer: 48
A 4.0 cm long straight wire carrying a current of 8 A is placed perpendicular to a uniform magnetic field of strength 0.15 T. The magnetic force on the wire is mN.
48
F = BIl 90
= 0.15 8 0.04 = 0.048 N
F = 48 mN
Answer: 48
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