A loop ABCDA, carrying current I = 12 A, is placed in a plane, consists of two semi-circular segments of radius R1 = 6 m and R2 = 4 m. The magnitude of the resultant magnetic field at center O is k 10-7 T. The value of k is . (Given 0 = 4 10-7 T m A-1) [figure]
Answer
1
Solution
Straight parts AB and CD lie on a line through O they give no field at O.
Field of a semicircular arc at its centre: B = 0 I4R
Arc BC (radius R2) carries current clockwise field into the plane: B2 = 0 I4R2
Arc DA (radius R1) carries current anticlockwise field out of the plane: B1 = 0 I4R1
B = 0 I4 ( 1R2 - 1R1 )
= 4 10-7 124 ( 14 - 16 )
= 12 10-7 112 = 1 10-7 T
k = 1
Answer: 1