The correct option for the value of vapour pressure of a solution at 45 C with benzene to octane in molar ratio 3 : 2 is : [At 45 C vapour pressure of benzene is 280 mm Hg and that of octane is 420 mm Hg. Assume ideal solution]
- 350 mm of Hg
- 160 mm of Hg
- 168 mm of Hg
- 336 mm of Hg
Answer
(4) 336 mm of Hg
Solution
Mole fractions: xbenzene = 35 = 0.6, xoctane = 25 = 0.4
By Raoult's law: ptotal = xB pB + xO pO
ptotal = 0.6 280 + 0.4 420
ptotal = 168 + 168 = 336 mm Hg
Answer: (4)