The following solutions were prepared by dissolving 10 g of glucose ( C6H12O6) in 250 ml of water (P1), 10 g of urea (CH4N2O) in 250 ml of water (P2) and 10 g of sucrose ( C12H22O11) in 250 ml of water (P3). The right option for the decreasing order of osmotic pressure of these solutions is :
- P3 > P1 > P2
- P2 > P1 > P3
- P1 > P2 > P3
- P2 > P3 > P1
Answer
(2) P2 > P1 > P3
Solution
= CRT = nVRT; with equal mass (10 g) and equal volume, n 1M (all are non-electrolytes).
Molar masses: urea = 60, glucose = 180, sucrose = 342 g mol-1
∴ : urea > glucose > sucrose ⇒ P2 > P1 > P3
Answer: (2)