Which of the following statements is incorrect?
- Pure sodium metal dissolves in liquid ammonia to give blue solution.
- NaOH reacts with glass to give sodium silicate.
- Aluminium reacts with excess NaOH to give Al(OH)3.
- NaHCO3 on heating gives Na2CO3.
Answer
(3) Aluminium reacts with excess NaOH to give Al(OH)3.
Solution
(1) Correct: alkali metals dissolve in liquid ammonia giving a blue solution due to ammoniated electrons.
(2) Correct: 2NaOH + SiO2 Na2SiO3 + H2O
(3) Incorrect: with excess NaOH, aluminium forms soluble sodium tetrahydroxoaluminate(III), not Al(OH)3:
2Al + 2NaOH + 6H2O 2Na+[Al(OH)4]- + 3H2
(4) Correct: 2NaHCO3 Na2CO3 + H2O + CO2
Answer: (3)