If an air bubble of diameter 2 mm rises steadily through a liquid of density 2000 kg/m3 at a rate of 0.5 cm/s, then the coefficient of viscosity of liquid is Poise. (Take g=10 m/s2)
- 0.88
- 8.8
- 88.8
- 0.088
Answer
(2) 8.8
Solution
The bubble rises with terminal velocity, so
Stokes' drag = upthrust - weight of air (negligible)
6 rv = 43 r3 g ⇒ = 2r2 g9v
r = 1 mm = 10-3 m, v = 0.5 cm/s = 5 10-3 m/s
= 2 10-6 2000 109 5 10-3 = 0.040.045
⇒ = 0.89 Pa s = 8.9 poise ≈ 8.8 poise ∵ 1 Pa s = 10 poise
Answer: (2)