The enthalpy of formation of ethane (C2H6) from ethylene by addition of hydrogen where the bond-energies of C-H, C-C, C=C, H-H are 414 kJ, 347 kJ, 615 kJ and 435 kJ respectively is − kJ
Answer
125
Solution
CH2=CH2 + H-H CH3-CH3
H = Σ BE (bonds broken) − Σ BE (bonds formed)
∵ broken: 1 C=C, 1 H–H; formed: 1 C–C, 2 C–H (the other four C–H bonds remain)
⇒ H = (615 + 435) − (347 + 2 × 414)
= 1050 − 1175 = −125 kJ
Answer: 125