Two reactions are given below: 2Fe(s) + 32O2(g) Fe2O3(s), H = -822 kJ/mol C(s) + 12O2(g) CO(g), H = -110 kJ/mol Then enthalpy change for following reaction 3C(s) + Fe2O3(s) 2Fe(s) + 3CO(g) is kJ/mol.
Answer
492
Solution
Hess's law: required reaction = 3 × (ii) − (i)
H = 3(-110) - (-822)
= -330 + 822
= +492 kJ/mol
Answer: 492