When a coil is placed in a time dependent magnetic field the power dissipated in it is P. The number of turns, area of the coil and radius of the coil wire are N, A and r respectively. For a second coil number of turns, area of the coil and radius of the coil wire are 2N, 2A and 3r respectively. When the first coil is replaced with second coil the power dissipated in it is 2 P. The value of is .
- 36
- 128 2
- 16
- 64
Answer
(1) 36
Solution
Induced emf: =NA dBdt NA
Coil radius a: A= a2 a A
Wire length =N(2 a) N A, wire cross-section = r2
Rcoil= N(2 a) r2 N Ar2
P= 2Rcoil N2A2r2N A=NA3/2r2
P'P=(2)(2)3/2(3)2=2 2 2 9
=36 2
P'=36 2 P= 2 P =36
Answer: (1)