Combustion of glucose ( C6H12O6) produces CO2 and water. The amount of oxygen (in g) required for the complete combustion of 900 g of glucose is : [Molar mass of glucose in g mol-1 = 180]
- 32
- 480
- 800
- 960
Answer
(4) 960
Solution
C6H12O6 + 6O2 6CO2 + 6H2O
Moles of glucose = 900180 = 5 mol
1 mol glucose needs 6 mol O2, so O2 needed = 5 6 = 30 mol
∴ Mass of O2 = 30 32 = 960 g
Answer: (4)