Ionization potential of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy 12.1 eV. According to Bohr's theory, the spectral lines emitted by hydrogen will be
- one
- two
- three
- four
Answer
(3) three
Solution
Energy after absorption: -13.6 + 12.1 = -1.5 eV
En = - 13.6n2 eV = -1.51 eV n = 3
Number of spectral lines = n(n-1)2 = 3 22 = 3 (3 → 2, 3 → 1, 2 → 1)
Answer: (3)