PYQSide ExamsMy practice

Atoms · Question 42

AIPMT 2006MCQMedium📈 Topic in 12% papers+4−1
1

Ionization potential of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy 12.1 eV. According to Bohr's theory, the spectral lines emitted by hydrogen will be

  1. one
  2. two
  3. three
  4. four

Answer

(3) three

Solution

Energy after absorption: -13.6 + 12.1 = -1.5 eV

En = - 13.6n2 eV = -1.51 eV n = 3

Number of spectral lines = n(n-1)2 = 3 22 = 3 (3 → 2, 3 → 1, 2 → 1)

Answer: (3)

AIPMT 2006

Keep practising — Atoms

2

The total energy of an electron in the first excited state of hydrogen atom is about -3.4 eV. Its kinetic energy in this state is

  1. 3.4 eV
  2. 6.8 eV
  3. -3.4 eV
  4. -6.8 eV
AIPMT 2005
3

Energy levels A, B and C of a certain atom corresponding to increasing values of energy i.e. EA < EB < EC. If 1, 2 and 3 are wavelengths of radiations corresponding to transitions C to B, B to A and C to A respectively, which of the following relations is correct?

  1. 3 = 1 + 2
  2. 3 = 1 2 1 + 2
  3. 1 + 2 + 3 = 0
  4. 32 = 12 + 22
AIPMT 2005
4

The Bohr model of atoms

  1. Assumes that the angular momentum of electrons is quantized.
  2. Uses Einstein's photoelectric equation.
  3. Predicts continuous emission spectra for atoms.
  4. Predicts the same emission spectra for all types of atoms.
AIPMT 2004
5

In which of the following systems will the radius of the first orbit (n = 1) be minimum?

  1. doubly ionized lithium
  2. singly ionized helium
  3. deuterium atom
  4. hydrogen atom
AIPMT 2003
6

The energy of hydrogen atom in nth orbit is En, then the energy in nth orbit of singly ionised helium atom will be

  1. 4En
  2. En/4
  3. 2En
  4. En/2
AIPMT 2001
7

Maximum frequency of emission is obtained for the transition

  1. n = 2 to n = 1
  2. n = 6 to n = 2
  3. n = 1 to n = 2
  4. n = 2 to n = 6
AIPMT 2000
8

When an electron makes a transition from n = 4 to n = 2, then the emitted line spectrum will be

  1. first line of Lyman series
  2. second line of Balmer series
  3. first line of Balmer series
  4. second line of Paschen series
AIPMT 2000

All Atoms PYQs →

PDFDownload Atoms PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All NEET Physics chapters