The total energy of electron in the ground state of hydrogen atom is -13.6 eV. The kinetic energy of an electron in the first excited state is
- 6.8 eV
- 13.6 eV
- 1.7 eV
- 3.4 eV
Answer
(4) 3.4 eV
Solution
First excited state: n = 2
E2 = - 13.622 = -3.4 eV
As per NCERT (Bohr model), K.E. = -En
K.E. = 3.4 eV
Answer: (4)