The pair of species with the same bond order is
- O22-, B2
- O2+, NO+
- NO, CO
- N2, O2
Answer
(1) O22-, B2
Solution
Bond order = 12(Nb-Na)
O22- (18 electrons): 12(10-8)=1
B2 (10 electrons): 12(6-4)=1
O2+ = 2.5, NO+ = 3 ; NO = 2.5, CO = 3 ; N2 = 3, O2 = 2
O22- and B2 both have bond order 1.
Answer: (1)