The magnetic flux linked to a circular coil of radius R is = 2t3 + 4t2 + 2t + 5 Wb The magnitude of induced emf in the coil at t = 5 s is
- 192 V
- 108 V
- 197 V
- 150 V
Answer
(1) 192 V
Solution
By Faraday's law, | | = d dt
| | = 6t2 + 8t + 2
At t = 5 s:
| | = 6(25) + 8(5) + 2 = 150 + 40 + 2
| | = 192 V
Answer: (1)