A long solenoid has 1000 turns. When a current of 4 A flows through it, the magnetic flux linked with each turn of the solenoid is 4 10-3 Wb. The self-inductance of the solenoid is
- 2 H
- 1 H
- 4 H
- 3 H
Answer
(2) 1 H
Solution
Total flux linkage: N = LI
L = N I = 1000 4 10-34
= 1 H
Answer: (2)