A long solenoid of diameter 0.1 m has 2 104 turns per meter. At the centre of the solenoid, a coil of 100 turns and radius 0.01 m is placed with its axis coinciding with the solenoid axis. The current in the solenoid reduces at a constant rate to 0 A from 4 A in 0.05 s. If the resistance of the coil is 10 2 , the total charge flowing through the coil during this time is
- 16
- 32
- 16
- 32
Answer
(2) 32
Solution
Charge through the coil: q = R (independent of the time taken)
Field inside the solenoid: B = 0 n I
= N 0 n I r2
= 100 4 10-7 2 104 4 (0.01)2
= 32 2 10-5 Wb
q = 32 2 10-510 2
= 3.2 10-5 C
q = 32
Answer: (2)