PYQSide ExamsMy practice

Structure of Atom · Question 33

NEET 2013MCQMedium📈 Topic in 38% papers+4−1
1

Based on equation E = -2.178 10-18 J ( Z2n2 ), certain conclusions are written. Which of them is not correct ?

  1. Equation can be used to calculate the change in energy when the electron changes orbit.
  2. For n = 1, the electron has a more negative energy than it does for n = 6 which means that the electron is more loosely bound in the smallest allowed orbit.
  3. The negative sign in equation simply means that the energy of electron bound to the nucleus is lower than it would be if the electrons were at the infinite distance from the nucleus.
  4. Larger the value of n, the larger is the orbit radius.

Answer

(2) For n = 1, the electron has a more negative energy than it does for n = 6 which means that the electron is more loosely bound in the smallest allowed orbit.

Solution

(1) Correct: E = Ef - Ei can be found from the equation for any two orbits.

(2) Not correct: for n = 1 the energy is the most negative, so the electron is most tightly (not loosely) bound in the smallest allowed orbit.

(3) Correct: as per NCERT, the negative sign means the energy of the bound electron is lower than that of a free electron at infinite distance (E = 0).

(4) Correct: rn = 52.9 n2Z pm ⇒ radius increases with n.

Answer: (2)

NEET 2013

Keep practising — Structure of Atom

2

The value of Planck's constant is 6.63 10-34 J s. The speed of light is 3 1017 nm s-1. Which value is closest to the wavelength in nanometer of a quantum of light with frequency of 6 1015 s-1 ?

  1. 50
  2. 75
  3. 10
  4. 25
NEET 2013
3

According to law of photochemical equivalence the energy absorbed (in ergs/mole) is given as (h = 6.62 10-27 ergs, c = 3 1010 cm s-1, NA = 6.02 1023 mol-1)

  1. 1.196 108
  2. 2.859 105
  3. 2.859 1016
  4. 1.196 1016
NEET 2013 (Karnataka)
4

The orbital angular momentum of a p-electron is given as

  1. h 2
  2. 3 h2
  3. 32 h
  4. 6 h2
AIPMT 2012 (Mains)
5

Maximum number of electrons in a subshell with l = 3 and n = 4 is

  1. 14
  2. 16
  3. 10
  4. 12
AIPMT 2012 (Prelims)
6

The correct set of four quantum numbers for the valence electron of rubidium atom (Z = 37) is

  1. 5, 1, 1, + 12
  2. 6, 0, 0, + 12
  3. 5, 0, 0, + 12
  4. 5, 1, 0, + 12
AIPMT 2012 (Prelims)
7

According to the Bohr theory, which of the following transitions in the hydrogen atom will give rise to the least energetic photon ?

  1. n = 6 to n = 1
  2. n = 5 to n = 4
  3. n = 6 to n = 5
  4. n = 5 to n = 3
AIPMT 2011 (Mains)
8

The total number of atomic orbitals in fourth energy level of an atom is

  1. 8
  2. 16
  3. 32
  4. 4
AIPMT 2011 (Prelims)
9

The energies E1 and E2 of two radiations are 25 eV and 50 eV respectively. The relation between their wavelengths i.e., 1 and 2 will be

  1. 1 = 2
  2. 1 = 2 2
  3. 1 = 4 2
  4. 1 = 12 2
AIPMT 2011 (Prelims)
10

If n = 6, the correct sequence for filling of electrons will be

  1. ns (n-2)f (n-1)d np
  2. ns (n-1)d (n-2)f np
  3. ns (n-2)f np (n-1)d
  4. ns np (n-1)d (n-2)f
AIPMT 2011 (Prelims)
11

A 0.66 kg ball is moving with a speed of 100 m/s. The associated wavelength will be (h = 6.6 10-34 J s)

  1. 6.6 10-32 m
  2. 6.6 10-34 m
  3. 1.0 10-35 m
  4. 1.0 10-32 m
AIPMT 2010 (Mains)

All Structure of Atom PYQs →

PDFDownload Structure of Atom PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All NEET Chemistry chapters