Maximum number of electrons in a subshell with l = 3 and n = 4 is
- 14
- 16
- 10
- 12
Answer
(1) 14
Solution
l = 3 ⇒ f subshell (here 4f).
Number of orbitals in a subshell = 2l + 1 = 2(3) + 1 = 7
Each orbital holds a maximum of 2 electrons.
∴ Maximum number of electrons = 2(2l + 1) = 2 7 = 14
Answer: (1)