The correct set of four quantum numbers for the valence electron of rubidium atom (Z = 37) is
- 5, 1, 1, + 12
- 6, 0, 0, + 12
- 5, 0, 0, + 12
- 5, 1, 0, + 12
Answer
(3) 5, 0, 0, + 12
Solution
Electronic configuration of Rb (Z = 37): [Kr] 5s1
∴ The valence electron is in the 5s orbital.
⇒ n = 5, l = 0 (s subshell), ml = 0, ms = + 12
Answer: (3)