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Inverse Trigonometric Functions · Question 14

JEE Main 2025 (Online) 4th April Evening ShiftMCQMedium📈 Topic in 16% papers+4−1
1

The sum of the infinite series -1 ( 74 )+ -1 ( 194 )+ -1 ( 394 )+ -1 ( 674 )+ is :

  1. 2+ -1 ( 12 )
  2. 2- -1 ( 12 )
  3. 2- -1 ( 12 )
  4. 2+ -1 ( 12 )

Answer

(3) 2- -1 ( 12 )

Solution

Numerators 7, 19, 39, 67, have second differences constant (12, 20, 28): they are 4n2+3

Tn= -1 ( 4n2+34 )= -1 (n2+ 34 )= -1 11+ (n2- 14 )

Tn= -1 (n+ 12 )- (n- 12 )1+ (n+ 12 ) (n- 12 )

Tn= -1 (n+ 12 )- -1 (n- 12 )

Sn= r=1nTr= -1 (n+ 12 )- -1 ( 12 ) (telescoping)

As n , -1 (n+ 12 ) 2

S = 2- -1 ( 12 )

Answer: (3)

JEE Main 2025 (Online) 4th April Evening Shift

Keep practising — Inverse Trigonometric Functions

2

If y = ( 3 + -1 x2 ), then (x - y)2 + 3y2 is equal to .

JEE Main 2025 (Online) 2nd April Evening Shift
3

Let S = \x : -1x = + -1x + -1(2x + 1) \. Then x S(2x - 1)2 is equal to .

JEE Main 2025 (Online) 29th January Morning Shift
4

( -1 35 + -1 513 + -1 3365 ) is equal to:

  1. 3365
  2. 1
  3. 3265
  4. 0
JEE Main 2025 (Online) 28th January Morning Shift
5

Let [x] denote the greatest integer less than or equal to x. Then the domain of f(x) = -1(2[x] + 1) is:

  1. (- , )
  2. (- , ) - \0\
  3. (- , -1] [0, )
  4. (- , -1] [1, )
JEE Main 2025 (Online) 28th January Evening Shift

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