1
Considering the principal values of the inverse trigonometric functions, -1 ( 32x + 12 1 - x2 ), - 12 < x < 1 2, is equal to
- -5 6 - -1x
- 5 6 - -1x
- 6 + -1x
- 4 + -1x
Answer
(3) 6 + -1x
Solution
Put x = , where = -1x.
- 12 < x < 1 2 - 6 < < 4, and 1 - x2 = (as > 0)
32x + 12 1 - x2 = 6 + 6
= ( + 6 )
Now 0 < + 6 < 5 12, which lies in [- 2, 2 ], so
-1 ( ( + 6 ) ) = + 6
= 6 + -1x
Answer: (3)
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