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Inverse Trigonometric Functions · Question 13

JEE Main 2025 (Online) 4th April Morning ShiftMCQMedium📈 Topic in 19% papers+4−1
1

Considering the principal values of the inverse trigonometric functions, -1 ( 32x + 12 1 - x2 ), - 12 < x < 1 2, is equal to

  1. -5 6 - -1x
  2. 5 6 - -1x
  3. 6 + -1x
  4. 4 + -1x

Answer

(3) 6 + -1x

Solution

Put x = , where = -1x.

- 12 < x < 1 2 - 6 < < 4, and 1 - x2 = (as > 0)

32x + 12 1 - x2 = 6 + 6

= ( + 6 )

Now 0 < + 6 < 5 12, which lies in [- 2, 2 ], so

-1 ( ( + 6 ) ) = + 6

= 6 + -1x

Answer: (3)

JEE Main 2025 (Online) 4th April Morning Shift

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2

The sum of the infinite series -1 ( 74 )+ -1 ( 194 )+ -1 ( 394 )+ -1 ( 674 )+ is :

  1. 2+ -1 ( 12 )
  2. 2- -1 ( 12 )
  3. 2- -1 ( 12 )
  4. 2+ -1 ( 12 )
JEE Main 2025 (Online) 4th April Evening Shift
3

If y = ( 3 + -1 x2 ), then (x - y)2 + 3y2 is equal to .

JEE Main 2025 (Online) 2nd April Evening Shift
4

Let S = \x : -1x = + -1x + -1(2x + 1) \. Then x S(2x - 1)2 is equal to .

JEE Main 2025 (Online) 29th January Morning Shift
5

( -1 35 + -1 513 + -1 3365 ) is equal to:

  1. 3365
  2. 1
  3. 3265
  4. 0
JEE Main 2025 (Online) 28th January Morning Shift
6

Let [x] denote the greatest integer less than or equal to x. Then the domain of f(x) = -1(2[x] + 1) is:

  1. (- , )
  2. (- , ) - \0\
  3. (- , -1] [0, )
  4. (- , -1] [1, )
JEE Main 2025 (Online) 28th January Evening Shift

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