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Conic Sections

JEE Main 2025 (Online) 29th January Evening ShiftNumericalHard📈 Topic in 50% papers+4
Ques. 1JEE Main 2025, 29 January (Evening Shift)

Let y2=12x be the parabola and S be its focus. Let PQ be a focal chord of the parabola such that (SP)(SQ)= 1474. Let C be the circle described taking PQ as a diameter. If the equation of a circle C is 64x2+64y2- x-64 3 y= , then - is equal to .

Answer

1328

Solution

y2=12x: a=3, S(3,0); P(3t2,6t), Q ( 3t2,- 6t ); SP SQ= 9(1+t2)2t2= 1474

⇒ 12t4-25t2+12=0 ⇒ t2= 34 or 43; the term -64 3y needs t=- 32

⇒ P ( 94,-3 3 ), Q(4,4 3)

[figure]

Diameter form: (x- 94 )(x-4)+(y+3 3)(y-4 3)=0 ⇒ 64x2+64y2-400x-64 3y=1728

∴ =400, =1728 ⇒ - =1328

Answer: 1328

Keep practising — Conic Sections

Ques. 2JEE Main 2025, 28 January (Morning Shift)

Let ABCD be a trapezium whose vertices lie on the parabola y2 = 4x. Let the sides AD and BC of the trapezium be parallel to y-axis. If the diagonal AC is of length 254 and it passes through the point (1, 0), then the area of ABCD is

  1. 758
  2. 1258
  3. 252
  4. 754
Ques. 3JEE Main 2025, 28 January (Morning Shift)

Let the equation of the circle, which touches x-axis at the point (a, 0), a > 0 and cuts off an intercept of length b on y-axis be x2 + y2 - x + y + = 0. If the circle lies below x-axis, then the ordered pair (2a, b2) is equal to

  1. ( , 2 + 4 )
  2. ( , 2 - 4 )
  3. ( , 2 - 4 )
  4. ( , 2 + 4 )
Ques. 4JEE Main 2025, 28 January (Morning Shift)

Let E1 : x29 + y24 = 1 be an ellipse. Ellipses Ei's are constructed such that their centres and eccentricities are same as that of E1, and the length of minor axis of Ei is the length of major axis of Ei+1 (i 1). If Ai is the area of the ellipse Ei, then 5 ( i=1 Ai ), is equal to .

Ques. 5JEE Main 2025, 28 January (Evening Shift)

If the midpoint of a chord of the ellipse x29 + y24 = 1 is ( 2, 4/3), and the length of the chord is 2 3, then is:

  1. 26
  2. 18
  3. 22
  4. 20
Ques. 6JEE Main 2025, 28 January (Evening Shift)

If A and B are the points of intersection of the circle x2 + y2 - 8x = 0 and the hyperbola x29 - y24 = 1 and a point P moves on the line 2x - 3y + 4 = 0, then the centroid of PAB lies on the line:

  1. x + 9y = 36
  2. 9x - 9y = 32
  3. 4x - 9y = 12
  4. 6x - 9y = 20
Ques. 7JEE Main 2025, 28 January (Evening Shift)

Let A and B be the two points of intersection of the line y + 5 = 0 and the mirror image of the parabola y2 = 4x with respect to the line x + y + 4 = 0. If d denotes the distance between A and B, and a denotes the area of SAB, where S is the focus of the parabola y2 = 4x, then the value of (a + d) is .

Ques. 8JEE Main 2025, 24 January (Morning Shift)

Let the product of the focal distances of the point ( 3, 12 ) on the ellipse x2a2+ y2b2=1, (a>b), be 74. Then the absolute difference of the eccentricities of two such ellipses is

  1. 1-2 2 3
  2. 1- 3 2
  3. 3-2 22 3
  4. 3-2 23 2
Ques. 9JEE Main 2025, 24 January (Morning Shift)

Let circle C be the image of x2+y2-2x+4y-4=0 in the line 2x-3y+5=0 and A be the point on C such that OA is parallel to x-axis and A lies on the right hand side of the centre O of C. If B( , ), with <4, lies on C such that the length of the arc AB is (1/6)th of the perimeter of C, then - 3 is equal to

  1. 4- 3
  2. 3
  3. 4
  4. 3+ 3
Ques. 10JEE Main 2025, 24 January (Evening Shift)

If the equation of the parabola with vertex V ( 32,3 ) and the directrix x+2y=0 is x2+ y2- xy-30x-60y+225=0, then + + is equal to :

  1. 6
  2. 8
  3. 7
  4. 9
Ques. 11JEE Main 2025, 24 January (Evening Shift)

The equation of the chord, of the ellipse x225+ y216=1, whose mid-point is (3,1) is :

  1. 5x+16y=31
  2. 48x+25y=169
  3. 4x+122y=134
  4. 25x+101y=176

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