The first and second ionization constants of H2X are 2.5 10-8 and 1.0 10-13 respectively. The concentration of X2- in 0.1 M H2X solution is 10-15 M. (Nearest Integer)
Answer
100
Solution
H2X H+ + HX-; Ka1 = 2.5 10-8
HX- H+ + X2-; Ka2 = 1.0 10-13
Ka2 Ka1, [H+] comes almost entirely from the first step
[H+] [HX-]
Ka2 = [H+][X2-][HX-] ⇒ [X2-] Ka2
[X2-] = 1.0 10-13 M = 100 10-15 M
Answer: 100