Two resistors of 100 each are connected in series with a 9 V battery. A voltmeter of 400 resistance is connected to measure the voltage drop across one of the resistors. The voltmeter reading is V.
- 3
- 2
- 4
- 4.5
Answer
(3) 4
Solution
Voltmeter in parallel with one resistor:
Rp = 100 400100 + 400 = 80
Total resistance: R = 80 + 100 = 180
Current: I = 9180 = 0.05 A
voltmeter reading = IRp = 0.05 80 = 4 V
Answer: (3)