Two infinite identical charged sheets and a charged spherical body of charge density ' ' are arranged as shown in figure. Then the correct relation between the electrical fields at A, B, C and D points is: [figure]
- | EA | = | EB |; EC > ED
- EA = EB; EC = ED
- EC ED; EA > EB
- EA > EB; EC = ED
Answer
(3) EC ED; EA > EB
Solution
Field of an infinite plane sheet: E = 2 0, independent of distance, directed away from the positive sheet.
Field of the charged sphere outside it: E = 14 0 Qx2, radially outward (x = distance from its centre).
Points A and B (between the sheets): the two sheet fields are equal and opposite they cancel.
Only the sphere's field acts at A and B. A is nearer to the sphere than B | EA | > | EB | (both along the same line, towards left).
Points C and D (outside the sheets): the sheet fields add, 0 — towards left at C and towards right at D.
The sphere's field also points left at C and right at D, but D is much nearer to the sphere than C its contribution is larger at D.
EC and ED differ in direction as well as in magnitude: EC ED
Answer: (3)