The light rays having photons of energy 4.2 eV are falling on a metal surface having a work function of 2.2 eV. The stopping potential of the surface is
- 6.4 V
- 2 eV
- 2 V
- 1.1 V
Answer
(3) 2 V
Solution
Einstein's photoelectric equation: eV0 = h - 0
eV0 = 4.2 eV - 2.2 eV = 2 eV
V0 = 2 V (stopping potential is measured in volt, not eV)
Answer: (3)