An electromagnetic wave of wavelength ' ' is incident on a photosensitive surface of negligible work function. If 'm' mass is of photoelectron emitted from the surface has de-Broglie wavelength d, then :
- = ( 2hmc ) d2
- = ( 2mhc ) d2
- d = ( 2mch ) 2
- = ( 2mch ) d2
Answer
(4) = ( 2mch ) d2
Solution
Work function 0 KE of photoelectron = hc
de Broglie wavelength: d = hp = h 2m KE KE = h22m d2
hc = h22m d2
= ( 2mch ) d2
Answer: (4)