An electron is accelerated through a potential difference of 10,000 V. Its de Broglie wavelength is (nearly) : (me = 9 10-31 kg)
- 12.2 10-12 m
- 12.2 10-13 m
- 12.2 10-14 m
- 12.2 nm
Answer
(1) 12.2 10-12 m
Solution
As per NCERT, for an electron accelerated through a potential V:
= h 2meV = 1.227 V nm
⇒ = 1.227 104 nm = 1.227100 nm
= 1.227 10-11 m
∴ 12.2 10-12 m
Answer: (1)