The number of photons per second on an average emitted by the source of monochromatic light of wavelength 600 nm, when it delivers the power of 3.3 10-3 watt will be : (h = 6.6 10-34 J s)
- 1015
- 1018
- 1017
- 1016
Answer
(4) 1016
Solution
Energy of one photon: E = hc
= 6.6 10-34 3 108600 10-9
= 3.3 10-19 J
Number of photons per second: N = PE
= 3.3 10-33.3 10-19 = 1016
Answer: (4)