For the given reaction: [figure] 'P' is
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Answer
(2) [figure]
Solution
Hot acidic KMnO4 cleaves the C=C bond; each =CH– carbon (one H on it) is oxidised to –COOH.
C6H11-CH=CH-C6H11 KMnO4/H+ 2C6H11COOH
Both halves give the same product, cyclohexanecarboxylic acid, so 'P' is C6H11COOH.
Answer: (2)