The equilibrium concentrations of the species in the reaction A + B C + D are 2, 3, 10 and 6 mol L-1, respectively at 300 K. G for the reaction is (R = 2 cal/mol K)
- -137.26 cal
- -1381.80 cal
- -13.73 cal
- 1372.60 cal
Answer
(2) -1381.80 cal
Solution
Kc = [C][D][A][B] = 10 62 3 = 10
G = -2.303 RT Kc
= -2.303 2 300 10
= -1381.8 cal
Answer: (2)