Amines · Question 25

An organic compound (P) on treatment with aqueous ammonia under hot condition forms compound (Q) which on heating with Br2 and KOH forms compound (R) having molecular formula C6H7N. Names of P, Q and R respectively are.

1. Toluic acid, methylbenzamide, 2-methylaniline
2. Benzoic acid, benzamide, aniline
3. Benzoic acid, 4-methylbenzamide, 4-methylaniline
4. Phenylethanoic acid, phenylethanamide, benzamine

A hydrocarbon 'P' (C4H8) on reaction with HCl gives an optically active compound 'Q' (C4H9Cl) which on reaction with one mole of ammonia gives compound 'R' ( C4H11N). 'R' on diazotization followed by hydrolysis gives 'S'. Identify P, Q, R and S.

1. P=CH3-CH=CH-CH3, Q=CH3-CH2-CH2-CH2-Cl, R=CH3-CH2-CH2- NH2 |CH2, S=CH3-CH2- OH |CH2 |CH2
2. P=CH3-CH=CH-CH3, Q=CH3-CH2- Cl |CH-CH3, R=CH3-CH2- NH2 |CH-CH3, S=CH3-CH2- OH |CH-CH3
3. P = [figure] , Q = [figure] , R = [figure] , S = [figure]
4. P=CH3-CH2-CH=CH2, Q=CH3-CH2-CH2- Cl |CH2, R=CH3-CH2-CH2- CH3 |NH, S=CH3-CH2- OH | CH3 |CH

Consider the following reaction sequence [figure] The percentage of nitrogen in product 'T' formed is %. (Nearest integer) (Given molar mass in g mol-1 H : 1, C : 12, N : 14, O : 16)

[figure] Consider the above sequence of reactions. The number of bromine atom(s) in the final product (P) will be :

1. 6
2. 5
3. 1
4. 3

Which of the following amine(s) show(s) positive carbylamine test? Choose the correct answer from the options given below:

1. C Only
2. B, C and D Only
3. A and E Only
4. A and C Only

The descending order of basicity of the following amines is : Choose the correct answer from the options given below :

1. E > A > D > C > B
2. E > D > A > B > C
3. E > D > B > A > C
4. B > E > D > A > C

The major product (A) formed in the following reaction sequence is [figure]

1. [figure]
2. [figure]
3. [figure]
4. [figure]

Identify [A], [B] and [C], respectively in the following reaction sequence : [figure]

1. [figure]
2. [figure]
3. [figure]
4. [figure]

In the following reactions, which one is NOT correct?

1. [figure]
2. [figure]
3. [figure]
4. [figure]

The sequence from the following that would result in giving predominantly 3,4,5-Tribromoaniline is :

1. [figure]
2. [figure]
3. [figure]
4. [figure]